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IGCSE Mathematics · 3 marks
2/3A trapezium has parallel sides (y + 4) cm and (y + 1) cm and height (y + 2) cm. Its area is 264 cm². Show that 2y² + 9y − 518 = 0.
[3]What we read
- 1½ (y + 4 + y + 1)(y + 2) = 264
- 22y² + 5y + 4y + 10 = 264
- 32y² + 9y − 518 = 0
Your handwriting, transcribed first, so a misread never becomes a mark.
- M1Awarded.a correct expression for the area, set equal to 264Your first line is exactly this. Method mark banked.
- B1Awarded.the expansion seen anywhere in the working2y² + 5y + 4y + 10 is on the page in line 2.
- A1Lost.reaches the printed result with no errors or omissions264 was never doubled, so line 3 does not follow from line 2. That slip costs the completion mark.
A 3-mark “show that” part, marked point by point.
The trail
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No mystery totals along the way. Your working is transcribed before anything is marked, so a misread never becomes a mark.
Followed here: the A1 lost on the slip above.
- A1Official pointreaches the printed result with no errors or omissionsIGCSE Mathematics · 3 marks
- Lost264 was never doubled, so the final line does not follow from the working. The completion mark goes.
- The fixDouble both sides before expanding: 528, not 264. Corrected while the slip is fresh.Fixed is pencil, not green. The mark is not yours back until you prove it.
- Earned backTwelve days later the same point resurfaces, and this time it lands. Cleared.Proved on a different paper, so it counts.
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